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2 years ago

Evaluate the expression for the given values 5x + 3y when x=3 and y = 5

Mathematics

1 answer:

Leni [432]2 years ago

7 0

Answer:

Step-by-step explanation:

Using the substitution method

5(3) + 3(5) =

15 + 15 = 30

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On a horizontal number line, positive numbers are_____

Bond [772]

Answer:

the horizontal are called x-axis, while the vertical are called y-axis

8 0

2 years ago

Determine if the following are properties write y or n for each

Paul [167]

Answer:

Answers are below

Step-by-step explanation:

5+1=6 No

78+6=76+8 Yes, commutative property of addition

2x+(3x+4x)=(2x+3x)+4x Yes, associative property of addition

52+(-18)=(-52)+18 No

6+(-6)=0 Yes, identity property of addition

If these answers are correct, please make me Brainliest!

4 0

2 years ago

2x -2 = -200 whats the value of x

Elden [556K]

Answer:

Step-by-step explanation:

2x - 2 = - 200

Bringing like terms on one side

2x = - 200 + 2 = - 198

2x = - 198

x = - 198/2 = - 99

4 0

2 years ago

Read 2 more answers

Which of the following is an equation of the line that passes through the point (−2, 3) and is perpendicular to the graph of the

Ludmilka [50]

The equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

Explanation:

The given equation is $y=3 x-2$

Slope:

Since, the equation of the line is perpendicular to the equation $y=3 x-2$ , then, the slope is given by

$m=-\frac{1}{3}$

Hence, the slope is $m=-\frac{1}{3}$

Equation of the line:

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (-2,3) and the slope $m=-\frac{1}{3}$ , in the above formula, we get,

$y-3=-\frac{1}{3}(x+2)$

Simplifying, we get,

$y-3=-\frac{1}{3}x-\frac{2}{3}$

$y=-\frac{1}{3}x-\frac{2}{3}+3$

$y=-\frac{1}{3}+\frac{7}{3}$

Therefore, the equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

8 0

2 years ago

What percentage of the semi circle is shaded?

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0

1 year ago