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gregori [183]
3 years ago
11

Evaluate the expression for the given values 5x + 3y when x=3 and y = 5

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

30

Step-by-step explanation:

Using the substitution method

5(3) + 3(5) =

15 + 15 = 30

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3 years ago
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Describe the two-dimensional cross section that would be created by slicing the cylinder-shaped cheese block as shown.
masha68 [24]

Answer: A RECTANGLE ( It has four sides, its opposite sides are congruent and all its angles measure 90 degrees)

Step-by-step explanation:

For this exercise it is important to remember the definition of a "Cross section".

In Geometry a "Cross section" is defined as that shape obtained when a three-dimensional figure is sliced by a plane.

In this case, according to the information given in the exercise, the cheese block has the shape of a cylinder. This is the three-dimensional figure.

Observe in the picture attached in the exercise that the  cylinder-shaped cheese block is cut through perpendicular to its base.

By definition, when this perpendicular cut happens, the shape obtained is  a Quadrilateral which has four  equal  angles that measure 90 degrees and whosepposite sides are parallel have equal length.

Therefore, you can conclude that the two-dimensional cross section that would be created by slicing the cylinder-shaped cheese block perpendicular to its base,is: A RECTANGLE.

3 0
3 years ago
Can anyone help me please?
miss Akunina [59]

Answer:

  5. -18x^3y^4 +54x^2y^4

  6. 6x^2 -40x +50

Step-by-step explanation:

Use the distributive property. The factor outside parentheses multiplies each term inside parentheses.

__

<h3>5.</h3>

  (9xy)(-2x^2y^3+6xy)=(9xy)(-2x^2y^3)+(9xy)(6xy^3)\\\\=\boxed{-18x^3y^4+54x^2y^4}

__

<h3>6.</h3>

  (3x-5)(2x-10)=3x(2x-10)-5(2x-10)\\\\=6x^2-30x-10x+50=\boxed{6x^2-40x+50}

7 0
2 years ago
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Answer:

so sorry yarr my same question

I hope you other

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3 years ago
How do the graphs of the functions f(x)=<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B2%7D%29%5Ex" id="TexFormula1" titl
grin007 [14]

Step-by-step explanation:

f(x) = (3/2)ˣ

g(x) = (2/3)ˣ

These are examples of exponential equations:

y = a bˣ

If b > 1, the equation is exponential growth.

If 0 < b < 1, the equation is exponential decay.

So f(x) is an example of exponential growth, and g(x) is an example of exponential decay.

Also, 2/3 is the inverse of 3/2, so:

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