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Citrus2011 [14]
3 years ago
11

Find each percent of change. Round to the nearest whole percent if necessary. State whether the percent of change is an increase

or a decrease.
4. 125 centimeters to 87.5 centimeters
Mathematics
2 answers:
Goryan [66]3 years ago
5 0

Answer:

decrease

Step-by-step explanation:

Dahasolnce [82]3 years ago
3 0
Decrease hope this helped
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Please help WHAT IS THE PERCENT OF 39.8 out of 200 QUICK PLEASE
Masteriza [31]

Answer:

19.9%

Step-by-step explanation:

39.8/200 = 0.199 (move decimal two times)

19.9%

or you can just see what number get 200 to 100, which is by dividing by 2. What you do to the bottom you do to the top so 39.8/200 (divide both sides by 2)  = 19.9/100

which is 19.9%.

<u><em>Ace Carlos</em></u>

7 0
3 years ago
Select all the correct answers. 6^3×2^6 Which expressions are equal to 2^3 ? 2^6×3^3; 6^3; 12^3; 2^3×3^3; 12^6
beks73 [17]

Answer:

12^3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the domain and range of the relation show in the table
Ainat [17]
The domain will be all ur x values....so ur domain is { -3,-1,2,5 }
The range will be all ur y values...so ur range is { 0,2,4 }...keeping in mind, if the numbers repeat, u only have to write them once
6 0
3 years ago
Read 2 more answers
1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may
SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}

Then, the sum of all of these must be 78, that is:

C+P+PC=78

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

47+P+15=78

Simplifying:

62+P=78

Now we solve for P by subtracting 62 on both sides:

\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}

Therefore, there are 16 students in physics

3 0
1 year ago
Fencing encloses a rectangular backyard that measures 300 feet by 600 feet. A blueprint of the backyard is drawn on the coordina
liubo4ka [24]

Answer:

(x-15)^2+(y-30)^2=36

Step-by-step explanation:

we know that

The dimensions of the rectangular backyard in the actual are 300 feet by 600 feet

The dimensions of the rectangular backyard in the blueprint are 30 units by 60 units

therefore

If the radius of the circular flower garden in the actual is 60 feet

then

the radius of the circular flower garden in the blueprint is 6 units

Find the center of the radius in the blueprint

Remember that the circular flower garden is in the center o the backyard

so

To find out the center, determine the midpoint of the rectangular backyard

C((0+30)/2,(0+60)/2)

C(15,30)

The equation of a circle in center radius form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center

r is the radius

we have

(h,k)=(15,30)\\r=6\ units

substitute

(x-15)^2+(y-30)^2=6^2

(x-15)^2+(y-30)^2=36

4 0
3 years ago
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