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SOVA2 [1]
3 years ago
11

Um....help me with this question​

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

Step-by-step explanation:What is the quetion

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If x = 4 and y = 12, evaluate the following expression:
Vladimir79 [104]

Answer:

\displaystyle \frac{1}{3}

Step-by-step explanation:

Hi there!

\displaystyle \frac{x}{y}

We're given that x=4 and y=12. Plug these in:

=\displaystyle \frac{4}{12}\\\\=\displaystyle \frac{1}{3}

I hope this helps!

4 0
3 years ago
I would appreciate it if you help me pls asap !!
masha68 [24]

Answer:

BC= 20 units

Step-by-step explanation:

Since ∆ ABC is an equilateral triangle, all the sides are equal in length.

AC= BC

=>-y+23= 6y+2

=>-y-6y= 2-23

=>-7y= -21

=>y= 21/7

=>y= 3

BC = 6y+2 = 6(3)+2 = 18+2 = 20 units

7 0
3 years ago
Read 2 more answers
Which theorem accurately completes Reason A?
klio [65]

hich theorem accurately completes Reason A

3 0
3 years ago
Solve: 10 2/3+2h≤4 1/3
PtichkaEL [24]

Answer:

\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}

Step-by-step explanation:

\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}

6 0
3 years ago
What is the simplified form of the equation fraction 4 over 5 n minus fraction 1 over 5 equals fraction 2 over 5 n?
Gennadij [26K]
4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5

n = 1/2

6 0
3 years ago
Read 2 more answers
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