Answer:
The leading coefficient of the polynomial is -9.
Step-by-step explanation:
9 is the leading coefficient of this polynomial because if you rearrange the exponents from greatest to least, you will get this :
-9x3 + 5x2 + 7x -10
Your leading coefficient is the number included with your degree or highest exponent.
Six dozen cupcakes is 72. So in this case Kailyn made 88 cupcakes, but that was 72 more than Melissa made so Melissa only made 16.
Given problem is 
To simplify that we need to multiply and divide by conjugate of the denominator
conjugate of denominator 6+i will be 6-i as we just need to change sign of the imaginary part
Now multiply and divide by 6-i







Hence final answer is 
Answer: Found it
Step-by-step explanation: