If x is 5, then 6x = _____.

Mathematics

2 answers:

Amanda [17]2 years ago

7 0

Idk if I’m right but I’m going with 6=30

allochka39001 [22]2 years ago

5 0

If x = 5 and it is 6x then you would take 6 times 5 which equals 30.

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4(PX+1)=64 what is the value of x in terms of p and what is the value of x when p is -5 ?

Oksana_A [137]

Answer:

x = -3

Step-by-step explanation:

$4(PX+1)=64\\\\p= -5$

Substitute -5 for p in the given equation and solve

$4(-5(x)+1)=64\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\frac{4\left(-5x+1\right)}{4}=\frac{64}{4}\\\\Simplify\\-5x+1=16\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\-5x+1-1=16-1\\\\Simplify\\-5x =15\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\frac{-5x}{-5}=\frac{15}{-5}\\\\Simplify\\x = -3$

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2 years ago

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natima [27]

Well, 6 x 9 = 54 which means the answer is 54. Hope this helps :)

6 0

2 years ago

Read 2 more answers

Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$

Viktor [21]

When $n=0$ , we have

$5^{3^0} + 1 = 5^1 + 1 = 6$

$3^{0 + 1} = 3^1 = 3$

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for $n=k$ , that

$3^{k + 1} \mid 5^{3^k} + 1$

Now for $n=k+1$ , we have

$5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)$