Jack would have $9,317 more than Henry. I can’t really show work, sorry
The slope-intercept form of a line:
![y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to slope\\\\b\to y-intercept](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5C%5C%5Cm%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%5Cto%20slope%5C%5C%5C%5Cb%5Cto%20y-intercept)
We have:
![(-3,\ 2)\to x_1=-3,\ y_1=2\\(1,\ 5)\to x_2=1,\ y_2=5](https://tex.z-dn.net/?f=%28-3%2C%5C%202%29%5Cto%20x_1%3D-3%2C%5C%20y_1%3D2%5C%5C%281%2C%5C%205%29%5Cto%20x_2%3D1%2C%5C%20y_2%3D5)
Substitute:
![m=\dfrac{5-2}{1-(-3)}=\dfrac{3}{4}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B5-2%7D%7B1-%28-3%29%7D%3D%5Cdfrac%7B3%7D%7B4%7D)
![y=\dfrac{3}{4}x+b](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B3%7D%7B4%7Dx%2Bb)
Put the values of coordinates of the point (1, 5) to the equation of a line:
![5=\dfrac{3}{4}(1)+b\\\\5=\dfrac{3}{4}+b\qquad|-\dfrac{3}{4}\\\\b=4\dfrac{1}{4}](https://tex.z-dn.net/?f=5%3D%5Cdfrac%7B3%7D%7B4%7D%281%29%2Bb%5C%5C%5C%5C5%3D%5Cdfrac%7B3%7D%7B4%7D%2Bb%5Cqquad%7C-%5Cdfrac%7B3%7D%7B4%7D%5C%5C%5C%5Cb%3D4%5Cdfrac%7B1%7D%7B4%7D)
Answer: ![y=\dfrac{3}{4}x+4\dfrac{1}{4}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B3%7D%7B4%7Dx%2B4%5Cdfrac%7B1%7D%7B4%7D)
Tom--------------
>10 sq ft per minute
Tim-------------------
>3.5*10=35 sq ft per minute
Both painters (10+35)=45
sq ft per minute
let's assume a cubic unit crate----------> V1=1*1*1=1 feet3
<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq
ft
if the volume of the cube increases twice
V2=2 feet3 ------------------- > 2=x*x*x------------- >x=2^(1/3)
And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft
V2/V1=9.5244/6=1.5874
Therefore
If Tim and Tom-----------------------
> take 1 day----------- > to paint a crate V1
For the crate V2------------- > take 1.5874 days
assuming an 8-hour work day
0.5874*8=4.70 hr-------------- > 4 h 42 min
The answer is 1 day 4h 42 min
Since the pool is square, the four sides are equal.
Therefore the length of one side = sqrt(292) = 17.1 to the nearest tenth.