Question

Martin is studying sucrase activity. He added sucrose solution + sucrase solution + buffer of pH 5.6 in two tubes. He incubated them at 35°C and 100°C respectively. When he performed a confirmatory test, only the first test tube showed enzyme activity. How would you justify the inactivity of the enzyme in the second test tube?
a.the enzymes in the second test tube must have denatured at ph 5.6 since most enzymes work at neutral ph
b.The enzymes in the second test tube must have denatured at 1000C, since most enzymes degrade at such high temperatures.
c.Enzymes must have remained dormant at 1000C, since most of the enzymes remain inactive at such higher temperatures.

Answer 1

Answer:

b.The enzymes in the second test tube must have denatured at 1000C, since most enzymes degrade at such high temperatures.

Explanation:

Enzymes normally perform better at low to moderate temperatures. In the presence of high temperature (for example 100°C), the activity of the enzyme in tube B has been suppressed by the high temperature. On the other hand, tube A is at a low temperature and the activity of the enzyme in the tube was observed.

Answer 2

B. At high temperatures, the active site of the enzyme is damaged and it is no longer able to attack itself to the required substrate as its shape will no longer match.