15.
0.20*x = 0.01*x + 38 => 0.19*x = 38 =>( 19/100 )*x = 38 => x = 3800/19 => x = 200.
Four $5 bills and two $1 bills
In total it’s six bills
5(4)=20 and 1(2)=2
20+2=22
Probability is 0/12 since there are no blue lollipops in the bag.
You're given two points for f(t) and g(t) each. Two points, (x1,y1), and (x2,y2). In this case, x1 is always x1=0, since the time t starts counting at the earliest year given.
We know the form y=mx+b. m can be found a la (y2-y1)/(x2-x1), but remember x1 is 0. b can be found at f(0) or g(0), which we're already given; y1 for both cases.
I'm sorry, but I'm not giving a direct answer. Knowing the method, and being careful with calculations, should be more than sufficient.<span>it would be 22395-20808/5=317.4 f(t)
26508-26155/5= 70.6
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