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3 years ago

5

Robert is shooting arrows at a target. The experimental probability that one will hit a bull’s eye is 1/2. If Ravi shoots 20 arr

ows, how many times can he expect to hit a bull’s eye?

1 answer:

aleksandrvk [35]3 years ago

8 0

Answer:

10

Step-by-step explanation:

half of twenty is ten.

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Using the converse of Pythagorean Theorem and the law of sines and cosines solve the word problem.

Helga [31]

Answer:

It's the law of cosines

Step-by-step explanation:

law of cosines states that $c^{2} =a^{2} +b^{2} -2ab (cos(\alpha ))$

so we know that a = 7, b = 4, and alpha would be 135 degrees, so just plugging it in gets us 49+16-2*7*4*(-0.707) = 65 + 39.59 = 104.59

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3 years ago

What is the equation of the graph

balandron [24]

Answer:

y=6^x-2

Step-by-step explanation:

Start with the parent function, a^x. The graph looks like it has been translated b units down, so our function is a^x+b. Now at x=0, y=-2. So b=-2. Next at x=1, y=3. 3=a^(1)-2, a=6. y=6^x-2 is the equation

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3 years ago

Explain how you write products when there are not enough digits in the product to place a decimal point

Anni [7]

If you there isn't enough digits to place, just add zeroes to product to make it a full product or don't even use a decimal point at all.

6 0

3 years ago

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

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3 years ago

Solve for n: 5/50 = n/110<br><br> n = 5<br><br> n= 11<br><br> n = 500<br><br> n = 55

Rus_ich [418]

5/50=n/110
Do the cross product.
50*n=5(110)
50n=550
n=550/50
n=11
Answer: n=11.

6 0

3 years ago