<span>
2. FG= x +8 and AF = 9x - 6</span>
1.
area = L x w = 72
L = 2w
72 = 2w*w = 2w^2
divide by 2
36 = w^2
w = sqrt(36) = 6
l = 2*6 =12
perimeter = 2L +2W = 2*12 + 2*6 = 24+12 = 36
2.
sqrt(40)= 6.324555 cm ( round to 6.32 )
6.32 - 4 = 2.32 cm original length of a side
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
Answer:
Step-by-step explanation:
Figure it out
