1.)A rectangle has an area of 72 square centimeters and the length is twice the width. The perimeter of the rectangle
1 answer:
1.
area = L x w = 72
L = 2w
72 = 2w*w = 2w^2
divide by 2
36 = w^2
w = sqrt(36) = 6
l = 2*6 =12
perimeter = 2L +2W = 2*12 + 2*6 = 24+12 = 36
2.
sqrt(40)= 6.324555 cm ( round to 6.32 )
6.32 - 4 = 2.32 cm original length of a side
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hope this helps
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