Question

Let f(x)=100−10+e−0.1x .

Answer 1

What are you solving for?
If you are solving for × then I hope this helps

Let's solve for x.

f(x)= 100−10+e−0.1x

Step 1: Add 0.1x to both sides.

xf+0.1x=−0.1x+e+90+0.1x

xf+0.1x = e+90

Step 2: Factor out variable x.

x(f+0.1) = e+90

Step 3: Divide both sides by f+0.1.

x(f+0.1)/ f+0.1 =e+90/ f+0.1

x=e+90/ f+0.1

Answer:

x= e+90/ f+0.1

Answer 2

Answer:

f(-2) = 87.8

Step-by-step explanation:

Given :  function $f(x)=100-10e^{(-0.1x)}$

We have to find f(-2)

Consider the given function $f(x)=100-10e^{(-0.1x)}$

We have to find f (-2) that is value of function f(x) at x = -2

Put x = -2 in function given , we have,

$f(-2)=100-10e^{-0.1\left(-2\right)}$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=100-10e^{0.1\cdot \:2}$

Multiply , we have,

$=100-10e^{0.2}$

We know $e^{0.2}=1.22140\dots$

So, $10e^{0.2}=12.21403\dots$

Subsitute and solve, we have,

$f(-2)=100-12.21403\dots=87.78597\dots$

Thus, f(-2) = 87.8