A real world problem is considered a problem that can either be A: Solved in any method. B:has words and numbers So you would write for instant Charlie went to the store he bought 7 items that costed 21.99 how much money does he have left after spending it on the items? Can you solve it no you cannot why? Because it doesnt have the amount of money he was allowed to spend thats what missing information is. Now extra information is when there is something in the problem <span>you DO NOT NEED to solve. Hope that helps you out.</span>
Answer:
the degree of the polynomial is 5
Answer:
105
Step-by-step explanation:
273/13 × 5= 105
That's the correct answer
Answer:
option c
Step-by-step explanation:
option c is right..
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.