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3 years ago

9

What’s the solution to this equation? 84=42+ x/3

1 answer:

ZanzabumX [31]3 years ago

5 0

Let's solve your equation step-by-step.
84
=
42
+
x
3
Step 1: Simplify both sides of the equation.
84
=
42
+
x
3
84
=
42
+
1
3
x
84
=
1
3
x
+
42
Step 2: Flip the equation.
1
3
x
+
42
=
84
Step 3: Subtract 42 from both sides.
1
3
x
+
42
−
42
=
84
−
42
1
3
x
=
42
Step 4: Multiply both sides by 3.
3
*
(
1
3
x
)
=
(
3
)
*
(
42
)
x
=
126
Answer:
x
=
126

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Which of the choices best describes this arithmetic sequence?<br> -3, 1, 5, 9, 13,...

zloy xaker [14]

Answer:

Add by 4

Step-by-step explanation:

-3+4=1

1+4=5

5+4=9

9+4=13

3 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Someone help me please !!

Fantom [35]

Answer: A) 60°
The inscribed angle is half the measure of the arc.

3 0

3 years ago

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Rainbow [258]

For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82

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5 0

4 years ago

The product of two decimal is 1.5008 if one of them is 0.56 find the other?<br>

babymother [125]

Answer:

divide 1.5008 and 0.56

which will be 2.68

3 0

3 years ago