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Sedbober [7]
3 years ago
10

Determine whether the number is divisible by 5. Give a reason based on the tests for divisibility. 15

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0
15 is divisible by 5 because the last digit of 15 is 5.

A number is divisible by 5 if the last digit of the number ends in 0 or 5
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Felicia used 153 Yellow beads and some green beads for her art project. She used 9 times as many Yellow beads as green beads. Ho
Vlada [557]

Answer:

17

Step-by-step explanation:

To find the number of green beads that Felicia used, we first need to list out what we know.

Let x = number of green beads.

Yellow Beads = 153

So we get:

x*9 = 153

We divide both sides by nine to find the value of x.

\dfrac{x*9}{9}=\dfrac{153}{9}

x = 17

To see if we got the answer correct, let's substitute x.

x * 9 = 153

17 * 9 = 153

153 = 153

7 0
3 years ago
I need help with this question. Can someone help me with it? And show work!
kondor19780726 [428]

Answer:

B

Step-by-step explanation:

K=1/3=10

L=1/5=6

10+6=16

30-16=14

4 0
3 years ago
Read 2 more answers
Need help plz help me
forsale [732]
8200? 82,000? 820,000?
4 0
3 years ago
Cameron sponsor a fun raiser that 582 people attended he raise $6480 he charged $15 for balcony seats and $10 for crown seats ho
bagirrra123 [75]

Answer:

132 people bought balcony tickets and 450 bout ground tickets

Step-by-step explanation:

let x be balcony and y for ground

x+y=582

15x+10y=6480  solve by adding(subtracting)/eliminating process

multiply first equation by 15 to eliminate x:

15x+15y=8730

15x+10y=6480      subtract

15x+15y-15x-10y=8730-6480

5y=2250

y=2250/5=450

x+y=582

x=582-450=132

8 0
3 years ago
An electrician charges $40 to come to your house she also charges $55 for each hour that she works the electrician charges you a
s2008m [1.1K]
First lets remove the initial fee
190 - 40 = 150
150 is how much she is charging you per hour.
If each hour is 55, lets divide 150 by 55.
150 \div 55 = 2.7
She charged you for 2.7 hours (almost 3) of service
3 0
3 years ago
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