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Sedbober [7]
3 years ago
10

Determine whether the number is divisible by 5. Give a reason based on the tests for divisibility. 15

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0
15 is divisible by 5 because the last digit of 15 is 5.

A number is divisible by 5 if the last digit of the number ends in 0 or 5
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Indicate whether the lines are parallel, perpendicular, or neither. Justify your answer. X=4 and Y=-2
geniusboy [140]

Answer:

perpendicular

Step-by-step explanation:

x = 4 is a vertical line.

y = -2 is a horizontal line.

The lines are perpendicular.

6 0
3 years ago
the 5th and 6th grade students at jackson middle school are going on a field trip. there are 6 classes in the fitth grade, and e
Mariulka [41]
No because there are 20 multiplied by 3 is 60. So the answer would be 60+144=204x12=2448 but the last answer was still correct
4 0
2 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
Divide 54 into two parts so that four times the greater equals five time the less​
LUCKY_DIMON [66]
Let the both the parts be 'x' and 'y'
x>y
We know that 4x = 5y
so x = 5y/4
x + y = 54
Replacing x we get
(5y/4) + y = 54
(5y +4y)/4 = 54
9y = 216
y = 24
Replacing y in ' x+y = 54'
we get x = 30

Hence the larger part is 30 whereas the smaller part is 24
5 0
2 years ago
What’s the median of these two numbers ?<br> 13 and 13
ale4655 [162]

median: The number that occurs in the middle after arranging in ascending order of magnitude

;13 13

since both appeared in the middle,you add it and divide by 2

13+13/2

26/2

13

;The median is 13

8 0
3 years ago
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