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3 years ago

Which of the following is NOT a way to prove triangles similar?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

3 0

I think a because b and c and trying to explain the triangles

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You have 7 consecutive numbers, with the smallest number n.

Romashka [77]

Answer:

a) 7 numbers in term of n = n+1, n+2, n+3, n+4, n+5, n+6 and n+7

b) n+1+n+2+n+3+n+4+n+5+n+6+ n+7

= 7n+28

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

3 0

3 years ago

Efectúa las siguientes operaciones, aplicando la propiedad distributiva de la multiplicación. De ser posible simplifique los res

Alchen [17]

Answer:

Step-by-step explanation:

e) 3√2 (-3√6 -2 -6)

3√2 (-3√6 - 8)

-9√12 - 24√2

-9√(2^2 * 3) - 24√2

-18√3 - 24√2

6(-3√3 - 4√2)

f) -5√2 (3 + 2√2 - 6 - 1)

-5√2(-4 + 2√2)

20√2 - 20

20(√2 - 1)

7 0

3 years ago

Which graph represents the solution set to the system of inequalities? Please help thank you!

Greeley [361]

Answer:

bottom left graph should be correct

6 0

3 years ago

A company that makes hard candy have a standard bag of hard candy with 150 pieces. The hard candy has three distinct colors red,

anzhelika [568]

Answer:

The degrees of freedom, Df = The number of bags produced on Monday - 1

Step-by-step explanation:

The number of degrees of freedom is the limiting number of values that are logically not influenced by other values such that they are capable of having variation

The degrees of freedom = The sample size - 1 = N - 1

Therefore, the degrees of freedom, Df = The number of bags produced on Monday - 1

5 0

2 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

3 years ago