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2 years ago

Can you guys help out please asap

Mathematics

1 answer:

Brrunno [24]2 years ago

5 0

So think of a triangle (draw this out of you need to). So sine = opposite over hypotenuse
And cosine = adjacent over hypotenuse
So the sin of angle Q is 4/5 meaning the hypotenuse is 5 and the opposite side to that angle is 4. Use the Pythagorean theorem to solve for the adjacent side
a^2+b^2=c^2
a^2+16=25
a^2=9
So a= 3
So the side lengths are 4 and 3 and the hypotenuse is 5. Now solve for the cosine of angles P and Q and add those fractions together. If you need further help let me know and I can work it out with you!

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∠YXZ and ∠ZXW are adjacent and supplementary angles. If m∠YXZ = 37°, what is m∠ZXW?

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Answer: Choice A) 143 degrees

To get this answer quickly, you subtract the given angle (37) from 180 to get 180-37 = 143

The more longer answer would look something like this
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3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

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Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

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3 years ago