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loris [4]
3 years ago
13

Can you guys help out please asap

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0
So think of a triangle (draw this out of you need to). So sine = opposite over hypotenuse
And cosine = adjacent over hypotenuse
So the sin of angle Q is 4/5 meaning the hypotenuse is 5 and the opposite side to that angle is 4. Use the Pythagorean theorem to solve for the adjacent side
a^2+b^2=c^2
a^2+16=25
a^2=9
So a= 3
So the side lengths are 4 and 3 and the hypotenuse is 5. Now solve for the cosine of angles P and Q and add those fractions together. If you need further help let me know and I can work it out with you!
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Answer: x=27

Step-by-step explanation:

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Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

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3 years ago
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Answer:

Any real number

Step-by-step explanation:

Let your no.= x

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get number plus 1=x+1

 

so equation we get

2x+4-x-3=x+1

x+1=x+1

 

x=x

 

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Answer:

16 children and 11 adults

Equation 1: a + c = 27

Equation 2: 4a + c = 60

Step-by-step explanation:

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2 years ago
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