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olya-2409 [2.1K]
4 years ago
14

Name what the triangle is .

Mathematics
2 answers:
erma4kov [3.2K]4 years ago
8 0
It's an isosceles triangle because two of the sides are equal. An equilateral triangle is when all of the sides are equal, and a scalene triangle is when all of the side lengths are different. An acute triangle is when all three angle measures are less than 90 degrees. Hope this helps!
ollegr [7]4 years ago
5 0
Well scalene triangles are known as right triangles too and that is a right triangle. This is your answer, but let's make sure first.

Isosceles triangles are acute triangles.

Equilateral triangles are triangles that have the same degrees in each angle. (40*, 40*, 40*)

Acute triangles are acute triangles.

Your final answer is A. scalene

Hoped I helped!
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Of the 450 students in the 6th grade at Graceland middle school, 75% ride the bus to school. How many 6th grade students to not
DIA [1.3K]

Answer:

112 or 113

Step-by-step explanation:

75%=0.75

450*0.75=337.5

450-337.5=112.5

Or if 75% ride then 25% do not ride the bus.

450*0.25=112.5

Presumably you would round to 113

3 0
4 years ago
Find the slope of this line. *
Elden [556K]

Answer:

1

Step-by-step explanation:

Slope = y2 - y1 / x2 - x1 so, (0 - (-2)) / (1 - (-1)) == 2/2 = 1

3 0
3 years ago
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Need the properties not filled in on the right side
SVEN [57.7K]

m=91

200=4m+18-2m

200-18=182

182 divided by 2 = 91

7 0
4 years ago
-43/100 as a decimal
lutik1710 [3]

Answer:

-0.43

Step-by-step explanation:

100/-43

6 0
3 years ago
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This circle is centered at the origin, and the length of its radius is 8. What is
Kitty [74]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x² + y² = 64

____________________________________

\large \tt Solution  \: :

Standard equation of circle is :

\qquad \tt \rightarrow \: (x - h) {}^{2}  + (y - k) {}^{2}  =  {r}^{2}

  • \textsf{h = x - coordinate of centre of circle}

  • \textsf{k = y - coordinate of centre of circle}

  • \textsf{r = radius= 8}

Since the circle is centered at origin, h = k = 0

\qquad \tt \rightarrow \: (x - 0) {}^{2}  + (y - 0) {}^{2}  =  {8}^{2}

\qquad \tt \rightarrow \:  {x}^{2}  +  {y}^{2} = 64

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
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