Answer:
Option A is correct.
is the equation represent the point slope form gives the plant's height at any time.
Step-by-step explanation:
Point slope intercept form: For any two points 
and 
then,
the general form
for linear equations; where m is the slope given by:
Consider any two points from the table;
let A= (2 , 16) and B =(4, 32)
First calculate the slope of the line AB:
= 8
Therefore, slope of the line m = 8
Then,
the equation of line is:
Substitute the value of m=8 and (2, 16) above we get;
Therefore, the equation in point slope form which gives the plant's height at any time is; , where x is the time(months) and y is the plant height (cm)
Answer:
2/6
Step-by-step explanation:
there is only two fives with two dice, the dice only have six sides therefore the chances would be two out of five
Since eva is a slow reader pacing at 12 pages an hour, she would have to read for 4 hours over the week in order to read 48 pages total.
12x4=48
Answer:
volume of fodder=1/3pie R^2h=
l^2=r^2+h^2
l^2=(2.1)^2+(3.6)^2
l^2=4.441+12.96=17.37
l=
=4.17m
minimum area of polythene to cover fodder=pieRl=
the volume of fodder is 
and minimum area of polythene to cover fodder in the rainy seasonv47.18m^3
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
