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PilotLPTM [1.2K]

3 years ago

6

(4) Check my work please?

1 answer:

lawyer [7]3 years ago

7 0

You have the correct x and y values. Nice work.

x/3 = 3/4
x*4 = 3*3
4x = 9
x = 9/4

AC = AD+DC
AC = 4+x
AC = 4+9/4
AC = 16/4 + 9/4
AC = 25/4

AB^2 + BC^2 = AC^2
5^2 + y^2 = (25/4)^2
25 + y^2 = 625/16
y^2 = 625/16 - 25
y^2 = 625/16 - 400/16
y^2 = 225/16
y = sqrt(225/16)
y = 15/4

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Is this a linear function? One person sends an email to 2 people. Those 2 people send it to 4 people, and those 4 send it to 8 p

Mumz [18]

Yes; this is a linear function because you plug in a number and multiply it by two, so the function would be y=2x, which is linear despite the fact that it lacks a b value.

Hope this helps! :)

8 0

3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/

VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

$A = \frac{1}{2}bh$ (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

$\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)$

We can find the base by solving equation (1) for b:

$b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm$

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

$2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)$

$\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min$

Therefore, the base is decreasing at 2 cm/min.

I hope it helps you!

7 0

2 years ago

What expression represents the volume in cubic units?

S_A_V [24]

Answer:

C is correct

Step-by-step explanation:

7 0

3 years ago

What is 4x +12=20 proof

dimulka [17.4K]

4x+12=20
-12 -12
——————
4x=8
divide by 4 on both sides
x=2

3 0

3 years ago

what is the volume of the hamsta snack box with a width of 1 1/2 inches, a length of2 1/2 inches, and a height of 4 inches

jenyasd209 [6]

<u>Given:</u>

The width of the snack box is $1 \frac{1}{2} \ inches=\frac{3}{2} \ inches$

The length of the snack box is $2 \frac{1}{2} \ inches=\frac{5}{2} \ inches$

The height of the snack box is 4 inches.

We need to determine the volume of the hamsta snack box.

<u>Volume of the box:</u>

The volume of the box can be determined using the formula,

$V=L \times W \times H$

where L is the length, W is the width and H is the height of the box.

Substituting the values, we get;

$V=4 \times \frac{3}{2} \times \frac{5}{2}$

Simplifying, we get,

$V=\frac{60}{4}$

$V=15 \ in^3$

Thus, the volume of the Hamsta snack box is 15 cubic inches.

3 0

3 years ago