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3 years ago

(4) Check my work please?

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

You have the correct x and y values. Nice work.

x/3 = 3/4
x*4 = 3*3
4x = 9
x = 9/4

AC = AD+DC
AC = 4+x
AC = 4+9/4
AC = 16/4 + 9/4
AC = 25/4

AB^2 + BC^2 = AC^2
5^2 + y^2 = (25/4)^2
25 + y^2 = 625/16
y^2 = 625/16 - 25
y^2 = 625/16 - 400/16
y^2 = 225/16
y = sqrt(225/16)
y = 15/4

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I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

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Answer:

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360 + 240 = 600

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