And angle measures 54° more than the measure of its complementary angle what is the measure of each angle

1 answer:

4 0

Answer:
The measure of the angles are 72 degrees and 18 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
Let
x -----> the measure of an angle
y-----> the measure of he other angle
we know that
x+y=90 -----> y=90-x -----> equation A
x=y+54 ----> equation B
substitute equation B in equation A and solve for y
y=90-(y+54)
y=90-y-54
2y=36
y=18°
Find the value of x
x=y+54 -----> x=18+54=72°
therefore
The measure of the angles are 72 degrees and 18 degrees

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5X23X2 using properties to find the sum or product

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3 years ago

Josh has 4 times as many pears as leya, who has one half as many pears as amy. If josh has 32 pears how many does amy have?

arlik [135]

<h3>The number of pears Amy has is 16.</h3>

Step-by-step explanation:

Let J represent the number of pears Josh has.

Let L represent the number of pears Leya has.

Let A represent the number of pears Amy has.

From the question given above,

Josh (J) = 4 × Leya (L)

J = 4L ....... (1)

Leya (L) = ½ × Amy (A)

L = ½A ........ (2)

Next, we shall determine the number of pears Leya has. This can be obtained as follow:

From equation 1

J = 4L

But

Josh (J) = 32 pears

Thus,

32 = 4L

Divide both side by 4

L = 32 / 4

<h3>Leya (L) = 8 pears </h3>

Finally, we shall determine the number pears Amy has. This can be obtained as follow:

From equation 2

L = ½A

But

Leya (L) = 8 pears

Thus,

8 = ½A

Cross multiply

A = 8 × 2

<h3>Amy (A) = 16 pears </h3>

Therefore, Amy has 16 pears.

Learn more: brainly.com/question/20971657

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2 years ago

Read 2 more answers

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$