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zvonat [6]
3 years ago
9

sum_(n=0)^infinity (x+8)**n/(3**n) (a) Find the values of x for which the series converges. (Enter the smaller number first.) (

-11 Correct: Your answer is correct. , -5 Correct: Your answer is correct. ) (b) Find the sum of the series for those values of x.
Mathematics
1 answer:
Fed [463]3 years ago
5 0
Idk but probably the sum is 6367337282&363632$3!.??.):
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Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t
frozen [14]

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

 c^{2} =a^{2}+b^{2}+2abcos\alpha---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and \alpha is the angle between a and b .

In equation 1 , the maximum and minimum values of cos\alpha are 1 and -1.

 so the value of c  lies in between

⇒ \sqrt{a^{2}+b^{2}-2ab   } and  \sqrt{a^{2}+b^{2}+2ab  }   = |a-b| and |a+b|

Given a=13.2 and b=6.7 so the the side lies in between  |13.2-6.7| and |13.2+6.7|

  so the third side lies between 6.5 and 19.9

3 0
3 years ago
743 times 295 answer please
Mamont248 [21]
The answer is 219,775
5 0
3 years ago
Read 2 more answers
Can someone plz help me with #2, #3, #4, #14
Drupady [299]
#2 is 5
#3 is 18.9
#4 is 14.1
#14 is yes it does
8 0
3 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
Read 2 more answers
40 POINTS!!! WILL MARK BRAINLIEST!!!<br> What postulate or theorem are these triangles congruent by?
kondor19780726 [428]

Answer:

It could be AAA

Step-by-step explanation:

there are only angles and no sides that are labled

7 0
4 years ago
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