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KatRina [158]
4 years ago
8

sally states that a triangle can only have one obtuse or right angle however a triangle must have at least to acute angles is sa

lly correct explain

Mathematics
2 answers:
Crazy boy [7]4 years ago
5 0

Answer:

Yes Sally is correct

Step-by-step explanation:

We note that an obtuse angle = Angle larger than 90°

Acute angle = Angle lesser than 90°

Sum of angles in a triangle = 180°

Number of angles in  triangle = 3

Therefore, assuming the angles in the triangle are A, B and C where C is obtuse or at least 90°, then we have;

C ≥ 90° therefore taken as obtuse

A + B + C = 180°

A + B  = 180° - C

∴ A + B  = 180°- (≥90°) = ≤90°

Hence A + B   ≤ 90°

Which means A and B are less than 90°, therefore both acute

Therefore, a triangle can have only one angle (C in the above example) greater than or equal to 90° and at least two acute angles A and B in the above example.

artcher [175]4 years ago
3 0

Answer: Yes, Sally is correct.

Step-by-step explanation: Both of Sally's statements are mathematically correct, because to begin with the total of the sum of angles in a triangle is always equal to 180 degrees. An acute angle is less than 90 degrees and that means we can calculate three acute angles from a triangle.

Also an obtuse angle is greater than 90 degrees, but less than 180 degrees. That means, a triangle cannot have more than one obtuse angle. If for instance a triangle has an angle measuring 91 degrees (obtuse angle), then the other two angles will be divided between the remainder which is 89 degrees.

Also a triangle can only have one right angle (which measures 90 degrees). This implies that, in a right angled triangle, there cannot be another 90 degree angle, because that would reduce the shape to two angles only (which is not possible).

A triangle can contain at least two acute angles (and at most three acute angles) and all three angles in either case must add up to 180 degrees.

Please refer to the picture attached for more information.

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After 24 pencil had sharpened, the pencil sharpener receptacle is full. If receptacle is emptied in average of twice a day, how
stiks02 [169]

Answer:

12 Pencils Sharpened

Step-by-step explanation:

Since the sharpener receptacle is emptied out 2 times every day.

Do 24*2 to get 48 pencils sharpened each day.

Now do 48/20 to get how many pencils a single person sharpens each day. Resulting in 2.4 pencils each day for 1 person.

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3 years ago
A set of children’s blocks contains three shapes: long, flats, and cubes. There are three times as many longs as cubes and 30 fe
kati45 [8]

Answer:

<u>There are 270 longs</u>

Step-by-step explanation:

<u>Equations</u>

We must write the problem into a mathematical model that allows us to apply the properties of basic algebra and solve for the variable which must be adequately set up.

We have three unknowns: the number of long blocks, flats blocks, and cubes. The conditions are given:

  • There are three times as many longs as cubes
  • There are 30 fewer flats than longs.
  • There are 600 blocks in all

For the equation to be easier solved, let's set the variable as the number of cubes:

x = number of cubes

Considering the first condition, we have

3x = number of longs

3x-30 = number of flats

And finally:

x + 3x+3x-30=600

Joining like terms:

7x=630

Solving for x

\displaystyle x=\frac{630}{7}=90

Therefore, there are 3x = 3*(90) = 270 longs

Answer: there are 270 longs

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3 years ago
An airplane descends from an altitude of 32,000 feet above sea level to an altitude of 27,000 feet above sea level.
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3 0
4 years ago
A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

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dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0
4 years ago
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