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3 years ago

Find the quadratic equation for y=x^2+6x-7

Mathematics

1 answer:

LenKa [72]3 years ago

5 0

Answer:

x = -1 or x = 7

Step-by-step explanation:

From my understanding, y will be zero and you have to find the value of x.

Step 1: Middle term break

y = x² + 6x - 7

x² + 6x - 7 = 0

x² - 7x + x - 7 = 0

Step 2: Solve

x(x-7) + 1(x-7) = 0

(x+1) (x-7) = 0

x = -1 or x = 7

Therefore, the value of x is either -1 or 7.

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Write an equation of the line that a passes through the given point and has the given slope of

RoseWind [281]

Answer: -2x+5

Step-by-step explanation:

7 0

4 years ago

Order the decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?

igor_vitrenko [27]

Answer:

0.27, 0.42, 0.7 & 0.22, 0.4, 0.72

Step-by-step explanation:

decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?

Arranging in ascending order ( 0.7,0.27,0.42) would be 0.27, 0.42, 0.7

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 27/100, 42/100, 70/100

Arranging in ascending order(0.4,0.22,0.72) would be 0.22, 0.4, 0.72

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 22/100, 40/100, 72/100

I hope this was helpful, please mark as brainliest

3 0

3 years ago

On average the number of electronic keyboards sold in Michigan each year is 39,720, which is five times the average number of el

Lady_Fox [76]

Answer:

12,588, keyboards are sold each year in Montana

5 0

3 years ago

If sin theta = (4)/(7), theta in quadrant II, find the exact value of (a) cos theta (b) sin (theta + (pi) / (6) ) (c) cos (the

EleoNora [17]

Answer:

a) $\cos(\theta) = \frac{\sqrt[]{33}}{7}$

b) $\sin(\theta + \frac{\pi}{6})\frac{-3\sqrt[]{11}+4}{14}$

c) $\cos(\theta-\pi)=\frac{\sqrt[]{33}}{7}$

d) $\tan(\theta + \frac{\pi}{4}) = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}$

Step-by-step explanation:

We will use the following trigonometric identities

$\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)$

$\cos(\alpha+\beta) = \cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)$ $\tan(\alpha+\beta) = \frac{\tan(\alpha)+\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}$ .

Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that

$x^2+4^2 = 7 ^2$

which implies that $x=-\sqrt[]{49-16} = -\sqrt[]{33}$ . Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then

$\cos(\theta) = \frac{-\sqrt[]{33}}{7}$

b)Recall that $\sin(\frac{\pi}{6}) =\frac{1}{2} , \cos(\frac{\pi}{6}) = \frac{\sqrt[]{3}}{2}$ , then using the identity from above, we have that

$\sin(\theta + \frac{\pi}{6}) = \sin(\theta)\cos(\frac{\pi}{6})+\cos(\alpha)\sin(\frac{\pi}{6}) = \frac{4}{7}\frac{1}{2}-\frac{\sqrt[]{33}}{7}\frac{\sqrt[]{3}}{2} = \frac{-3\sqrt[]{11}+4}{14}$

c) Recall that $\sin(\pi)=0, \cos(\pi)=-1$ . Then,

$\cos(\theta-\pi)=\cos(\theta)\cos(\pi)+\sin(\theta)\sin(\pi) = \frac{-\sqrt[]{33}}{7}\cdot(-1) + 0 = \frac{\sqrt[]{33}}{7}$

d) Recall that $\tan(\frac{\pi}{4}) = 1$ and $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}=\frac{-4}{\sqrt[]{33}}$ . Then

$\tan(\theta+\frac{\pi}{4}) = \frac{\tan(\theta)+\tan(\frac{\pi}{4})}{1-\tan(\theta)\tan(\frac{\pi}{4})} = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}$

5 0

3 years ago

|x +2], if x>-1<br> Plz help

Fantom [35]

Answer:

Step-by-step explanation:

greater than 1 , is your teacher just giving you brain teaser questions? these seem like they are .. "out in the weeds" type of questions, not really useful math :/

3 0

3 years ago