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bija089 [108]
3 years ago
8

Need help these 3 math ?​

Mathematics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

I can't see the problem, sorry.

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Help pls ! <br> i’ll mark brainliest to whoever answers it right first.<br> thanks !
Bess [88]
About 90ft

step-by-step explanation: 1/2 (a+b) x h is area of trapezoid. So that would be 40
then area of circle is pi x radius squared. So that is 50.24 roughly.

so 50+40=90

and yeah

hope this helped :))
7 0
3 years ago
Answer CORRECTLY !!!!! Will mark brainliest !!!!
mash [69]

Answer:

g(q) = \frac{5q}{8}

Step-by-step explanation:

Given

- 7q + 12r = 3q - 4r

Rearrange making r the subject

Add 7q to both sides

12r = 10q - 4r ( add 4r to both sides )

16r = 10q ( divide both sides by 16 )

r = \frac{10q}{16} = \frac{5q}{8} , thus

g(q) = \frac{5q}{8}

4 0
3 years ago
Read 2 more answers
Calculate X3 dx .<br><br>A.×2 + c<br>B. 3X2 + c<br>c . x4 + c<br>D . x4/4+c
olga nikolaevna [1]
\LARGE \int x^3 dx = \frac{x^4}{4}+C

So the answer is choice D. You can check this by differentiating the right hand side and you'll get x^3 back again. 

This answer can be found by using the power rule for integrals. That rule is

\LARGE \int x^n dx = \frac{x^{n+1}}{n+1} + C
4 0
3 years ago
Find the value of f for which MATH is a parallelogram
melisa1 [442]
IF MATH is a parallelogram, then |AP| = |PH|, or, in other words,

2f-5 = 5f - 17.  solving for f:  12 = 3f, or f= 4.
7 0
3 years ago
Read 2 more answers
Match the circle equations in general form with their corresponding equations in standard form. x2 y2 − 4x 12y − 20 = 0 (x − 6)2
frosja888 [35]

The equation given is matched with the respective vertex forms.

<h3>What is the standard Equation for a circle ?</h3>

The standard equation for a circle is given by

(x-h)² + (y-k)² = r²

The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

5x²  + 5y²  − 10x + 20y − 30 = 0

(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

(x+3)²  + (y-4)²  = 35

The third equation is

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

The fourth equation is

5x²  + 5y²  − 10x + 20y − 30 = 0

(x-1)²  + (y+2)²   = 11

The fifth equation is

2x²  + 2y²  − 24x − 16y − 8 = 0

(x − 6)²  + (y − 4)²  = 56

To know more about standard equation of Circle

brainly.com/question/13658927

#SPJ1

7 0
1 year ago
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