F: R -> R, f(x) = ax + b;
f(1) = 8 => a + b = 8;
f(2) = 14 => 2a + b = 14 => a = 6 and b =2;
f(3) = 20 => 6*3 + 2 = 20 True;
f(4) = 26 => 4*6 + 2 = 26 True;
then, f:R -> R, f(x) = 6x + 2;
Answer:
D
Step-by-step explanation:
For simplify the work we can start to factorise all the possibles expressions:
2x + 8.
8 is multiple of 2, so it can became
2(x+4)
x^2 - 16 this is a difference of two squares, so it can be rewritten as:
(x+4)(x-4)
x^2 + 8x + 16
we have to find two numbers whose sum is 8 and whose product is 16
the two number are 4 and 4
it becames:
(x+4)(x+4)
x+ 4 can‘t be simplified
if we look at the expression, we can find that x-4 appears at the numerator so
x^2 - 16 must be at numerator
but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option
in fact
(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)
it became
(x+4)(x-4)/2 * 1/(x+4)(x+4)
(x-4)/2(x+4)
Answer: The steak costs $ 7.67.
Step-by-step explanation:
Given: Cost per pound of Rib-eye steaks = $8.52
Ms. Markum bought a 0.9-pound steak.
To find : cost of 0.9 pound steak =
Then cost of 0.9 pound steak = 0.9 x (Cost per pound of Rib-eye steaks )
= $ (0.9 x 8.52)
= $7.668 ≈ $ 7.67
Hence, the steak costs $ 7.67.
F(x)=x^2+3x+5
f(3+h)=(3+h)^2+3(3+h)+5
f(3+h)=9+6h+h^2+9+3h+5
f(3+h)=23+9h+h^2
Answer:
So the greatest common factor 15 and 21 is 3.
Step-by-step explanation:
