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Rasek [7]
3 years ago
14

The poly nominal 6x^2+x-15 has a factor of 2x-3 what is the other factor

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

3x+5

Step-by-step explanation:

\frac{6x^2+x-15}{2x-3} All I have done here is divide the polynomial by one of the factors

\frac{\left(2x-3\right)\left(3x+5\right)}{2x-3} You can see you have the same equation on the top as on the bottom, 2x-3.

(3x+5)

Hope this helps! Have a nice day. Please mark brainliest!

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These tables represent a quadratic function with a vertex at (0,3). What is the average rate of change for the interval from X =
Eva8 [605]

Answer:

-19

Step-by-step explanation:

The missing table is shown in the attachment.

Since the quadratic function has vertex at (0,3), its equation is of the form;

y = a {x}^{2}  + 3

To find the value of 'a' we substitute any other point from the table say (1,2) to get:

2 = a( {1)}^{2}  + 3

a = 2 - 3 =  - 1

Hence the function is

y =  -  {x}^{2} +  3

Now

f(10) =  - 100 + 3 =  - 97

f(9) =  - 81 + 3 =  - 78

The average rate of change from x=9 to x=10 is

\frac{f(10) - f(9)}{10 - 9}  =  \frac{ - 97 -  - 78}{1}  =   - 19

7 0
4 years ago
Find the average rate of change of f(x)=4x^2-6 on interval [1,a]​
stiv31 [10]

9514 1404 393

Answer:

  4a +4

Step-by-step explanation:

The average rate of change of f(x) on the interval is ...

  (f(a) -f(1))/(a -1)

  = ((4a² -6) -(4(1)² -6))/(a -1) = (4a² -4)/(a -1)

  = 4(a² -1)/(a -1) = 4(a +1) = 4a +4

The average rate of change on the interval is 4a +4.

4 0
3 years ago
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