Plzzzz help me I need help with 10!!!!

A stadium has 47,000 seats. Seats sell for $42 in Section A, $36 in Section B, and $30 in Section C. The number of seats in Sect

kupik [55]

Answer:

section A holds 23,500 Section B holds 11,750 And Section C holds 11,750

Step-by-step explanation:

Section A is half of the stadium so divide 47,00 by 2 you get 23,300 so that is Section A than b and c are the other half for divide 23,500 by 2 and you get 11,750

5 0

2 years ago

I need help with 1 & 2 tyvm

BabaBlast [244]

Answer:

1. x=17.5

2. x=77

Step-by-step explanation:

1. -x=-3x+35

=2x=35

x=17.5

2. -x/7+8=-3

=-x/7=-11

=-x=-77

x=77

5 0

2 years ago

Read 2 more answers

Problem Solving

KATRIN_1 [288]

by unitary method the exact answer is correct (2,920 glasses).

given, glasses of water each day = 8

therefore, by unitary method :

glasses of water in 365 day = $8*365 = 2920$

hence the total glasses of water in 365 days = 2,920

learn more about unitary method here:

brainly.com/question/23423168

#SPJ9

3 0

1 year ago

The Chang family is on their way home from a cross-country road trip. During the trip, the function D(t)=3260−55t can be used to

nadya68 [22]

Answer:

D(12) = 2,600 miles

It means a distance of 2,600 miles is already traveled from home after 12 hours

Step-by-step explanation:

To find D(12); all we have to do is to substitute the value of 12 for D

We have this as;

D(12) = 3260-55(12)

D(12) = 2,600

In the context of this problem, what this mean is that the distance away from home is 2,600 miles after traveling 12 hours

6 0

2 years ago

Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago