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3 years ago

What is the answer to this question and how do I get the answer

Mathematics

1 answer:

Svetlanka [38]3 years ago

7 0

I think it is something

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This is due tomorrow PLZ HELP IMMEDIATELY

horsena [70]

The value of X would be 9

8 0

3 years ago

Read 2 more answers

at a charity casino event, a woman begins playing a slot machine with $10 in quarters in her coin bucket. she plays 15 quarters

irina [24]

Answer:

265 quarters ($66.25)

Step-by-step explanation:

10$ in quarters is 250 quarters.

you subtract the 15 from winning (=235), then add 50 for the jackpot (=285). Subtract another 20 for her final plays (=265).

8 0

3 years ago

1. An outdoor art is a metal cube with edge length 39 feet. What is the volume of the cube in feet? In cubic yard? ( Can someone

Law Incorporation [45]

The volume of a cube is just the side length cubed...

V=s^3 in this case:

V=39^3=59319 ft^3

and in cubic yards it is:

59319 ft^3*(yd^3/27 ft^3)=2197 yd^3

5 0

3 years ago

Please help with this Calculus questions

Triss [41]

Answer:

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\frac{193}{100}=1.93$ .

Step-by-step explanation:

To find $\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du$ .

First, calculate the corresponding indefinite integral:

Integrate term by term:

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u}} =\int{2 d u} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant rule $\int c\, du = c u$

$\int{2 d u}} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u} = {\left(2 u\right)} + \int{\frac{2 u^{4}}{5} d u} - \int{\frac{3 u^{9}}{2} d u}$

Apply the constant multiple rule $\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$

$2 u - {\int{\frac{3 u^{9}}{2} d u}} + \int{\frac{2 u^{4}}{5} d u} = 2 u - {\left(\frac{3}{2} \int{u^{9} d u}\right)} + \left(\frac{2}{5} \int{u^{4} d u}\right)$

Apply the power rule $\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$

$2 u - \frac{3}{2} {\int{u^{9} d u}} + \frac{2}{5} {\int{u^{4} d u}}=2 u - \frac{3}{2} {\frac{u^{1 + 9}}{1 + 9}}+ \frac{2}{5}{\frac{u^{1 + 4}}{1 + 4}}$

Therefore,

$\int{\left(- \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2\right)d u} = - \frac{3 u^{10}}{20} + \frac{2 u^{5}}{25} + 2 u = \frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)$

According to the Fundamental Theorem of Calculus, $\int_a^b F(x) dx=f(b)-f(a)$ , so just evaluate the integral at the endpoints, and that's the answer.

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}=\frac{193}{100}$

$\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=0$

$\int_{0}^{1}\left( - \frac{3 u^{9}}{2} + \frac{2 u^{4}}{5} + 2 \right)du=\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=1\right)}-\left(\frac{u}{100} \left(- 15 u^{9} + 8 u^{4} + 200\right)\right)|_{\left(u=0\right)}=\frac{193}{100}$

6 0

3 years ago

Which function is the inverse of function of f if the domain of f is x > 0?<br> f(x) = x^2 + 6

levacccp [35]

Answer:

f⁻¹(x) = ± √x-6

Step-by-step explanation:

f(x) = x² + 6

y = x² + 6

x = y² + 6 ... replace x and y

solve y: y² = x - 6

y (f⁻¹(x)) = ± √x-6

4 0

3 years ago