Question

A woman earns $ 1,350 in interest from two accounts in one year. If she has three times as much invested at 7% as she does at 6%, how much does she have in each account?​

Answer 1

Answer:

The woman invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.

Step-by-step explanation:

We are given the following in the question:

Let x be the interest earned from 7% interest rate and y be the interest earned from 6% interest rate.

The woman invested has three times as much invested at 7% as she does at 6%.

Thus, we can write the equation:

$x = 3y$

The total interest is $1,350.

Thus, we can write the equation:

$1350 = \dfrac{7x}{100} + \dfrac{6y}{100}\\\\7x + 6y = 135000$

Solving the two equations by substitution method:

$7(3y) + 6y = 135000\\27y = 135000\\y = 5000\\x = 3(5000) = 15000$

Thus, she invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.