Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
<span>x=12 plus or minus the square root of 164 all divided by 2
or in decimal form </span>x = {12.403124237, -0.403124237}
X= 12 + y
So then plug in
12 + y + y = 12
2y=0
Y= 0
X + 0 = 12
X= 12
this is prob wrong lol but hopefully it helps
First - 8
second - 4
third - 12
fourth - 9
f(x) = -10
set the equation equal to -10 and solve for x:
-10 = -x-1
Add 1 to both sides:
-9 = -x
Divide both sides by -1:
x = 9
Answer:
Step-by-step explanation:
<u>Apply exponent rule:</u>
Add the numbers:
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