Huh? I don’t understand your question... please be more specific so we can help you
Answer:
Explanation:
The code provided is written in Java. The statement is provided right under the /*Type your code here*/. In Java, in order to case one primitive to another you simply need to type the primitive type that you are trying to cast too before the variable and within parenthesis. The output of the new code can be seen in the attached image below.
class LabProgram {
public static int convert(double d){
/* Type your code here */
return (int) d;
}
public static void main(String[] args) {
System.out.println(convert(19.9));
System.out.println(convert(3.1));
}
}
Answer:
131 packets
Explanation:
Given
W (link ) =0.5 M bits, and Ping packets ( P ) = 500bytes
To flood a target organization that has a bandwidth of W bits using a packet Mbits, you will require a W / P packet
P ( required ) = 500 * 8 = 4000 bits
therefore the W /P packet is calculated as
= 0.5 M bits / 4000 bits
given that : 1 M bits = 1,048,576 bits
0.5 M bits / 4000 bits= 131.07
hence approximately 131 packets/ sec is required to flood the target organization
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]
