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anzhelika [568]
3 years ago
7

Write convert() method to cast double to int

Computers and Technology
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

Explanation:

The code provided is written in Java. The statement is provided right under the /*Type your code here*/. In Java, in order to case one primitive to another you simply need to type the primitive type that you are trying to cast too before the variable and within parenthesis. The output of the new code can be seen in the attached image below.

class LabProgram {

   public static int convert(double d){

   /* Type your code here */

      return (int) d;

}

public static void main(String[] args) {

System.out.println(convert(19.9));

System.out.println(convert(3.1));

}

}

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What is the first thing you should do when you discover a computer is infected with malware? The second thing?
Goshia [24]

Answer:

Quarantine the computer.

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3 0
3 years ago
Which of the following is the best reason to use a macro?: *
marin [14]

Answer:c)You want to automate a repetitive task to save time

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This program works by taking the into and generating the preset output sequence. Other options are incorrect because it does not help in email functions, correction of the citation in documents or generation of the table.Thus, the correct option is option(c).

7 0
3 years ago
Which of the four digital-to-analog conversion techniques (ASK, FSK, PSK or QAM) is the most susceptible to noise? Defend your a
grigory [225]

Answer:

ASK

Explanation:

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3 0
2 years ago
Write a C function (NOT A COMPLETE PROGRAM) which uses the RETURNstatement to calculate and return the total cost for purchasing
stira [4]

Answer:

int calculate_cost(int quantity) {

   double cost = 0;

   if (quantity <= 20)

       cost = quantity * 23.45;

   else if (quantity >= 21 && quantity <= 100)

       cost = quantity * 21.11;

   else if (quantity > 100)

       cost = quantity * 18.75;

   

   return cost;

}

Explanation:

Create a function called calculate_cost that takes one parameter, quantity

Initialize the cost as 0

Check the quantity using if else structure. Depending on the quantity passed, calculate the cost. For example, if the quantity is 10, the cost will be $234.5

Return the cost

3 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
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