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3 years ago

Norman bought 5/6 pounds of cookies. He ate 3/5 cookies. What was the weight of the cookies he ate

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

Answer:

Half a pound.

Step-by-step explanation:

To find the number of pounds he ate, multiply the fractions.

$\frac{5}{6}*\frac{3}{5} = \frac{15}{30}=\frac{1}{2}$

He ate 1/2 a pound.

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2 years ago

What is 95% of 40?part. ___ = ___. percentwhole. 100 percent

Elena L [17]

1) According to that table we can write:

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2) So filling in we have:

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7 months ago

A motor boat travels 130km in 5 hours going upstream. It travels 220km going downstream in the same amount of time. What is the

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2 years ago

The value of a car after t years can be found using the formula V = C(1 - r)t, where V is the current value of the car, C is the

Stells [14]

The given formula is
$V = C(1-r)^{t}$

Therefore
$(1-r)^{t} = \frac{V}{C} \\\\ 1-r = ( \frac{V}{C} )^{1/t} \\\\ r = 1 - ( \frac{V}{C} )^{1/t}$

Given:
C = $25,000
V = $12,000
t = 4.5 years

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3 years ago

The athlete’s salary, in thousands, for the first two years is $400 and $400(1.05). Explain how to find her salary for each of t

enyata [817]

To find the salary for the next three years, we are going to use the formula for the nth term of a geometric sequence: $a_{n}=a_{1}r^{n-1}$
where
$a_{n}$ is the nth term of the sequence
$a_{1}$ is the first term in the sequence
$r$ is the common ratio
$n$ is the position of the term in the sequence

To check if the values $400 and 400(1.05) for a geometric sequence, we are going to find their common ratio. To find the common ratio, we are going to use the formula $r= \frac{a_{n} }{a_{n-1}}$
where
$a_{n}$ is the current term in the sequence
$a_{n-1}$ is the previous term in the sequence

We can infer from our values, that the current term of the sequence is 400(1.5), so $a_{n-1}=400(1.5)$ . That leaves 400 as the previous term, so $a_{n-1}=400$ . Lets replace those values in our formula to find $r$ :
$r= \frac{a_{n} }{a_{n-1}}$
$r= \frac{400(1.05)}{400}$
$r=1.05$

Now that we have our common ratio, we can replace it in our formula for the nth term to find the athlete's salary for each of the next three years. Notice that the first term of our sequence is $400, so $a_{1}=400$
$a_{n}=a_{1}r^{n-1}$
$a_{n}=400(1.05)^{n-1}$
$a_{3}=400(1.05)^{3-1}$
$a_{3}=400(1.05)^{2}$
$a_{3}=441$

$a_{4}=400(1.05)^{4-1}$
$a_{4}=400(1.05)^{3}$
$a_{4}=463.05$

$a_{5}=400(1.05)^{5-4}$
$a_{5}=400(1.05)^4$
$a_{5}=486.2025$

We can conclude that the athlete's salary for each of the next three years is: $441,$463.05,486.2025 respectively. Also, those vales for a geometric sequence because they share a common ratio, (1.05).

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2 years ago

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