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lana66690 [7]
3 years ago
15

Norman bought 5/6 pounds of cookies. He ate 3/5 cookies. What was the weight of the cookies he ate

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

Half a pound.

Step-by-step explanation:

To find the number of pounds he ate, multiply the fractions.

\frac{5}{6}*\frac{3}{5} = \frac{15}{30}=\frac{1}{2}

He ate 1/2 a pound.

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Each side is about 290mm long
4 0
3 years ago
The surface area of given figure is 200cm². i. Find height of triangle. ii. Find value of y. 80⁰ 5cm 5cm​
Orlov [11]

Answer:

the answer is 16 . the explanation is that because if you have. 200 cm y axis it overcomes the x of other 80

5 0
2 years ago
A bag contains 170 marbles. There are red, blue and yellow marbles in a ratio of 9:3:5. How many yellow marbles does the bag con
telo118 [61]

Answer:

50 yellow marbles.

Step-by-step explanation:

Information:

170 marbles

RED : BLUE : YELLOW

9 : 3 : 5

Solving:

To find out how many yellow parts there are, we need to find out how many marbles 5 parts account to.

Altogether, 9 + 3 + 5 = 17. This means there are 17 parts.

The bag contains 170 marbles and the ratio adds up to 17 parts.

We can figure out what 1 part of the ratio accounts to by dividing 170 by 17.

\frac{170}{17} = 10.

1 part = 10

Now remember yellow is 5 parts, now that we know that 1 part is 10, we need to multiply 10 by 5 to find out how many yellow marbles we have.

5 x 10 = 50.

Therefore we have 50 yellow marbles.

7 0
3 years ago
What is the value of x in the equation<br> 4z +16<br> 12<br> = х - 4?
Serhud [2]
<h3>Solution:</h3>

\frac{4x + 16}{12}  = x - 4 \\  =  > 4x + 16 = 12(x - 4) \\  =  > 4x + 16 = 12x - 48 \\  =  > 16 + 48 = 12x  - 4x \\  =  > 64 = 8x \\  =  > x =  \frac{64}{8}  \\  =  > x = 8

<h3>Answer:</h3>

x = 8

7 0
2 years ago
Ndicate the equation of the line through (2, -4) and having slope of 3/5.
lord [1]

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})~\hspace{10em} slope = m\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=\cfrac{3}{5}(x-2) \implies y+4=\cfrac{3}{5}x-\cfrac{6}{5} \\\\\\ y=\cfrac{3}{5}x-\cfrac{6}{5}-4\implies \implies y=\cfrac{3}{5}x-\cfrac{26}{5}

7 0
2 years ago
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