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3 years ago

Use linear combinations to solve v-w=-5 v+2w=4

1 answer:

4 0

V - w = -5...multiply by -1
v + 2w = 4
--------------
-v + w = 5 (result of multiplying by -1)
v + 2w = 4
--------------add
3w = 9
w = 9/3
w = 3

v - w = -5
v - 3 = -5
v = -5 + 3
v = -2

solution is : (-2,3)

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Answer:

A) P = 240

B) P + Po = 1040

C) P = 270.58

D) P+Po = 1070.58

E) Option B (compound interest) is better, as it generates more interest for the same inicial value, rate of interest and time

Step-by-step explanation:

The formula for simple interest is:

P = Po*r*t

Where P is the interest earned, Po is the inicial value, r is the rate of interest and t is the time.

The formula for compound interest is:

P+Po = Po*(1+r)^t

So we have that:

A) P = 800*0.06*5 = 240

B) P + Po = 800 + 240 = 1040

C) P+Po = 800*(1+0.06)^5 = 1070.58 -> P = 1070.58 - 800 = 270.58

D) P+Po = 1070.58

E) Option B (compound interest) is better, as it generates more interest for the same inicial value, rate of interest and time

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3 years ago

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Equation:
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3 years ago

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3 years ago

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Answer:

The probability that a student has a college degree or is not married is 0.8308.

Step-by-step explanation:

The information provided is:

Total number of high school seniors (N) = 650.

Number of seniors with a college degree (n (C)) = 400.

Number of seniors who were married, (n (M)) = 310.

Consider the Venn diagram below.

The probability of an event, say E, is the ratio of the favorable outcomes of E to the total number of outcomes of the experiment.

That is,

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes of E

N = total number of outcomes of the experiment.

The probability of the union of two events is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=\frac{n(A)+n(B)-n(A\cap B)}{N}$

Compute the probability that a student has a college degree or is not married as follows:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}$

From the Venn diagram:

n (C) = 400

n ( $M^{c}$ ) = N - n (M) = 650 - 310 = 340

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The value of P (C ∪ $M^{c}$ ) is:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}=\frac{400+340-200}{650}=0.83077\approx0.8308$

Thus, the probability that a student has a college degree or is not married is 0.8308.

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3 years ago

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Answer:

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3 years ago