so confusing i really need help with this math
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,

Hence, this is the required solution.
I'll focus on problem 19 and problem 22
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Problem 19
Answers:
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Explanation:
The horizontal lines are parallel. Note the arrow markers along the interior portion of the lines. These similar markers tell us how the lines pair up to be parallel to one another.
Since the horizontal lines are parallel, this means the angles in question are congruent. They are corresponding angles.
x+15 = 102
x = 102-15
x = 87
Which leads to
x+15 = 87+15 = 102
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Problem 22
Answer: y = 27
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Explanation:
We have a pair of alternate exterior angles. They are congruent due to the parallel lines.
Let's solve for y.
7y-55 = 3y+53
7y - 3y = 53+55
4y = 108
y = 108/4
y = 27
Answer: A=20.8, B=20.5, C=10, D=2, E=12.6
Explanation: It takes time, but all you have to do it make an equation adding all the sides together, which equals 85.9. Then find “a” and plug that back in to each side. (I’m pretty sure this is right, but sorry if I’m wrong)
Answer:

Step-by-step explanation: