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Mademuasel [1]
3 years ago
11

What are the signs of the coordinates in Quadrant 1?​

Mathematics
2 answers:
Vinvika [58]3 years ago
5 0
The signs of quadrant one is I. It looks like a capital i
natulia [17]3 years ago
3 0

Hello!

Answer:

<u><em>The correct answer is A. (+,+)</em></u>

Step-by-step explanation:

The two axes divide the coordinate plane into four sections called quadrants.

  • Quadrant l
  • Quadrant ll
  • Quadrant lll
  • Quadrant IV

Quadrant l ⇒ (+,+)

Quadrant ll ⇒ (-,+)

Quadrant lll ⇒ (-,-)

Quadrant lV ⇒ (+,-)

A is the final answer.

Hope this helps you!

Have a great day! :)

-Charlie

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Svetach [21]
The answer would be 7-x.
8 0
3 years ago
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Milo is volunteering at a food pantry. In the first hour, he packs 3 boxes every
garri49 [273]
14 boxes per hour
60/5=12
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Please I need help with this problem
Vikki [24]

Answer:

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8 0
3 years ago
The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (
sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

\dfrac{dr}{dt} = 1\text{ meter per hour}                

The height is decreasing at a rate 4 meter per hour  

\dfrac{dh}{dt} = -4\text{ meter per hour}

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

\pi r^2 h

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}

Putting all the values we get,

\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

3 0
3 years ago
Simplify. √ 240 10√ 24 2√ 30 6√40 4√15
Orlov [11]

240 = 16 * 15 = 4^2 * 15

So

√ 240 =  √(4^2 * 15) = 4√15

Answer

4√15

5 0
3 years ago
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