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notsponge [240]
3 years ago
7

A train travels at a constant speed of 24

Mathematics
2 answers:
guapka [62]3 years ago
4 0

Answer:

d=24h

Step-by-step explanation:

The table is

h        d

1        24

2       48

3       72

4       96

This relation can be presented as the following linear equation

d=24h

Because, the distance is defined as the product between the speed and the time. Also, we obtain this relation, by finding the slope of the given vales

m=\frac{96-24}{4-1}=\frac{72}{3}=24

Then, using one point, the slope and the point-slope formula, we have

y-y_{1}=m(x-x_{1})\\y-24=24(x-1)\\y=24x-24+24\\y=24x

Where y=d and x=h.

Therefore, the expression that models this situation is

d=24h

Masja [62]3 years ago
3 0

Answer:

Step-by-step explanation:

d = 24 x h

since d is the distance in order to get that we need to multiply the speed times time and get the answer

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How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

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