y = 2x -5
y= -3x + 1
Here both the equations are in y = mx + b
where m is the slope and b is the y intercept
y =2x -5, the slope = 2 and b intercept = -5
y= -3x + 1, the slope = -3 and b intercept = +1
Both the equations have different slope. So there should be a single solution
Yes, the system of equations have a solution
<em><u>Answer: 10.</u></em>
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<em><u>Step-by-step explanation:</u></em>
<em><u>DIVISION. 120/12.</u></em>
<em><u>That is hard! Here's a trick.</u></em>
<em><u>12x9= 99=9=108. Or 12x6=66+6=72.</u></em>
<em><u>We will stick with 12x9, that equals 108.</u></em>
<em><u>We should add another 12 until we get to 120. </u></em>
<em><u>108+12=120. That is 10 times. The trick was...</u></em>
<em><u>dividing by 12 is hard, so lets say 12x4. I can put 4 and 4 together.</u></em>
<em><u>44 then and another 4. That is 48. So 12x4=48.</u></em>
<em><u /></em>
Answer: x= 4 or x = -1
Step-by-step explanation:
x = 4 or x = -1. If the fraction is defined, the denominator cannot equal 0.:x + 2 neq 0 and 3 x - 4 neq 0Convert in
Answer:
Step-by-step explanation:
The alternate exterior angles with angle 11 are angle 13 and angle 5.Step-by-step explanation: Two angles are called Alternate exterior angles if1. They are on the exterior side of parallel lines and2. Lie on the opposite sides of the transversal line.It is given that r\\ s andt\\ u. From the figure it is noticed that the angle 13 and angle 5 are on the exterior side of parallel lines and they lie on the opposite sides of the transversal line.Therefore alternate exterior angles with angle 11 are angle 13 and angle 5.
Question 6 of 25
Which expression gives the area of the triangle shown below?
A. ac
O Box
OC. (*)
OD (aco)
SUBMIT
gnnh
