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Bumek [7]
4 years ago
13

I need the inverse operation for questions 1,3,7,9

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
7 0

3. g(x) = (x-3)^2 -5

Replace g(x) with y

y = (x-3)^2 -5

Switch the x and the Y:

x = (y-3)^2 -5

Solve for y:

Add 5 to both sides:

x + 5 = (y-3)^2

Take the square root of both sides:

+ /- SQRT(x+5) = y -3

Add 3 to both sides:

y = +/- SQRT(x +5) +3

The solution is both the positive and negative:

SQRT(x +5) +3 and -SQRT(x+5) +3

7. Following the same steps as 3

The answer is SQRT(x-2) -6 and -SQRT(X-2) -6

9. Following thw same steps as 3.

The answer is SQRT(2(x+4)) +2 and - SQRT(2(x+4))

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Identify the domain and range
UkoKoshka [18]

Answer:

Domain: 1 ≤ x ≤ 4

Range : 1 ≤ f(x) ≤ 4

Step-by-step explanation:

The domain of a function f(x) is the limit within which the values of x varies.

Here, in the graph, it shows that the maximum value of x is 4 and the minimum value of x is 1.

Therefore, the domain of the function is 1 ≤ x ≤ 4

Again the range of a function f(x) is the limit within which the values of f(x) vary.

Here, the graph shows that the maximum value of f(x) is 4 and the minimum value of f(x) is 1.

Therefore, the range of the function f(x) is 1 ≤ f(x) ≤ 4. (Answer)

6 0
3 years ago
Solve by completing the square? Could you please work it out step-by-step?
DaniilM [7]
16 n^2 -10n + 129 = 8n^2 -8

We collect the terms:
8n^2 -10n + 137 = 0

The steps for completing the square:

1) Move the "non X" (or "non N") term to the right:

8n^2 -10n  = -137

<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125 </span>

3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36

</span>
n^2 -1.2n +.36 = <span>-17.125 +.36

Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root( <span> <span> <span> -16.765 </span> </span> </span> )
That's about as far as I can go.

4 0
3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
A farmer will divide a 1/4 acre plot of land into three equal-sized sections what will be the size of each section?
Natalija [7]
1/4:3= 1/4•1/3=1/12acre - size of each section

1/2•1/5=1/10yard
8 0
3 years ago
Read 2 more answers
Find the molar mass in grams of <br> CaSO4 * 2H20<br> grams
adoni [48]

Answer:

172 g/mol

Step-by-step explanation:

CaSO4 . 2H2O

Atomic mass of

Ca = 40

S = 32

O = 16

H = 1

Molar mass = 40 + 32 + (16×4) + 2{(1×2)+16}

= 72 + 64 + 2(18)

= 136 + 36

= 172 g/mol

4 0
3 years ago
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