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2 years ago

Use the equation xy= 12.6. Find the value of y when x=7

Mathematics

1 answer:

Marat540 [252]2 years ago

6 0

Answer: y = 1.8

Step-by-step explanation:

xy = 12.6 If x is 7 but 7 in the equation for x

7y = 12.6 Divide both sides by 7

y = 1.8

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Suppose that there are two types of tickets to a show:Advance and same-day. Advance tickets cost $35 and same day tickets cost $

sdas [7]

Answer: 30 $15 tickets and 20 $35 tickets

Step-by-step explanation:

.X%2BY=50

2.15X%2B35Y=1150

From eq. 1,

15X%2B15Y=750

Subtract from eq. 2,

15X%2B35Y-15X-15Y=1150-750

20Y=400

Y=20

Then,

X%2B20=50

X=30

30 $15 tickets and 20 $35 ticket

Hope it helps

5 0

2 years ago

What is the HCF and LCM of 268 and 244

Ray Of Light [21]

Answer:

HCF = 4

LCF = 16348

HOPE THIS HELPS :)

5 0

2 years ago

The number of students who attended Lincoln Middle School last year was 860. This year, the attendance has increased to 1032 stu

Tju [1.3M]

Answer:

120 %.

Step-by-step explanation:

That is (1032 * 100) / 860 %

= 120 %

7 0

2 years ago

If a person bikes 2.4 miles in 10 minutes how far can a bike in 1.5 hours

Annette [7]

1.5 hour = 90 minute. Each 10 minute =2.4 miles so it's 2.4•9=21.6 The answer the person can bikes 21.6 miles in 1.5 hours.

4 0

3 years ago

Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

4 0

2 years ago

Read 2 more answers