Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down,drag into the correct position in the answer box.Release your mouse button when the item is place. If you change your mind,drag the item to the trash can,click the trash and to clear all your answers. Divide the following polynomials,then place the answer in the proper location on the grid. Write the answer in descending powers of x. 9x^2-18x-7 divided by (3x+1)

Answer 1

Answer:

$\boxed{\sf \ \ 9x^2-18x-7 \ \ divided \ by \ (3x+1) \ is \ (3x-7) \ }$

Step-by-step explanation:

Hello,

let's find a and b reals so that

$9x^2-18x-7=(3x+1)(ax+b)$

$(3x+1)(ax+b)=3ax^2+(3b+a)x+b$

we identify the terms in $x^2$

   9 = 3a

we identify the terms in x

   -18 = 3b + a

we identify the constant terms

   -7 = b

so ti goes with a = 9/3 = 3, b = -7

so we can write

$9x^2-18x-7=(3x+1)(3x-7)$

so $9x^2-18x-7 \ divided \ by \ (3x+1) \ is \ (3x-7)$

hope this helps