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adelina 88 [10]

2 years ago

15

Is the sequence 4, 8, 12, 16, 20, ... a geometric sequence? If it is a geometric sequence, what is the common ratio?

1 answer:

vovangra [49]2 years ago

3 0

Answer and Step-by-step explanation:

This sequence is NOT a geometric sequence.

It is an arithmetic sequence, because the numbers are going up using addition, going up each time by 4.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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11,17,18,19,23,21,14 what is the median

Tema [17]

The median is 18.
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8 0

3 years ago

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How can you approximate the square root of 30?

Ierofanga [76]

You can approximate the square root of 30 by taking the square root of a number close to it. This is called local linearization. You can take the square root of 36, which is 6, and the square root of 25, which is 5, and state that the square root of 30 is approximately somewhere between 5 and 6

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3 years ago

Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =

goldenfox [79]

Answer:

$f(x)=-1(x-2)^2+8$

Step-by-step explanation:

Given:

The quadratic function is given as:

$f(x)=-x^2+2x+4$

The standard form of a quadratic function is given as:

$f(x)=a(x-h)^2+k$ , where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by square method.

$-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4$

Now, $f(x)=-x^2+2x+4$ can be rewritten as:

$f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8$

Therefore, the standard form of the function is:

$f(x)=-1(x-2)^2+8$

7 0

3 years ago

Can a moderator ip ban me from this site cos that'd be memorable

marishachu [46]

Answer:

why what happened?

Step-by-step explanation:

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Factor the algebraic expression.<br> 20a + 12

Studentka2010 [4]

Answer:

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Step-by-step explanation:

20a + 12 = 32a

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3 years ago

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