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harina [27]
3 years ago
15

What is 3h^2= h^2 + 18​

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

h = ±9

Step-by-step explanation:

3h²= h² + 18​   (subtract h²) from both sides

3h² - h²= 18​

2h²= 18​   (divide both sides by 2)

h² = 18/2

h² = 9

h = ±√18

h = ±9

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2 years ago
Shen needs to read 2 novels each month
Sonbull [250]

Answer:

Equation: N = 2M, Shen needs to read 26 novels in 13 months

Step-by-step explanation:

Given : Shen needs to read 2 novels each month.

i.e. In One month , the number of novels read by Shen = 2

Let N be the number of novels Shen needs to read in M months.

Then , N = 2 M

Thus , the equation relating N to M : N = 2 M

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5 0
2 years ago
Find the domain and range of these functions. a) the function that assigns to each pair of positive integers the first integer of
Sonja [21]

Answer:

a) Domain = N x N, Range = N

b) Domain = N, Range = {1,2,3,....,9}

c) Domain = {0, 1, 00, 01, 10, 11,...}, Range = {.....,-4, -3, -2, -1, 0, 1, 2, 3,......}

d) Domain = {1,2,3,4,.....}, Range = {0, 1, 2, 3, 4,.....}

e)  Domain = {0, 1, 01, 10, 11,....}, Range = {1, 11, 111, 1111, 11111,.....}

Step-by-step explanation:

a) The function that assigns to each pair of positive integers the first integer of the pair will have domain equal to all pairs of natural numbers i.e, N x N where N = {1,2,3,.....} since the set of natural numbers has all positive integers.

Domain = {(x,y) | x ∈ N and y ∈ N}

The range is any integer so it will be a set of natural numbers N = {1,2,3,....}

b) Here, we have domain of each positive integer so we will have

Domain = {1,2,3,....}

Range is the largest decimal digit of the positive number which can be any number from 1 to 9

So, Range = {1,2,3,4,....,9}

c) Domain is a bit string i.e.

Domain = {0, 1, 00, 01, 10, 11,...}

The range includes the differences of 1's and 0's in the string. According to this, we can have all positive and non-positive (0 and negative integers) values in the range. So, it will be a set of all integers

Range = {.....,-4, -3, -2, -1, 0, 1, 2, 3,......}

d) We again have domain equal to set of positive integers i.e,

Domain = {1,2,3,4,.....}

Range is the largest integer that does not exceed the square root of the number. According to this, image of 1 will be 0, image of 2 will be 1. So, range will be a set of whole numbers.

Range = {0, 1, 2, 3, 4,.....}

e) Domain = {0, 1, 01, 10, 11,....} (A bit string)

Longest string of ones in the string will give the range

Range = {1, 11, 111, 1111, 11111,.....}

3 0
3 years ago
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