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yawa3891 [41]
3 years ago
10

Which is the graph of f(x) = square root 4x

Mathematics
1 answer:
Step2247 [10]3 years ago
4 0

The graph of f(x) = sqrt( 4x) looks like this. So choose the one that looks like the image attached.

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Is brainly working for anyone right now
Tom [10]

Answer:

no i cant see the answers haha

Step-by-step explanation:

4 0
3 years ago
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Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.
DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

Ways = ^nP_r

This gives

Ways = ^4P_3

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

Ways = ^nC_r

This gives

Ways = ^4C_3

Evaluate

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Hence, the number of ways when the choice is not relevant is 4

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4 0
2 years ago
The scatter plot shows the number of cds
saw5 [17]
It's too blurry to read. If you tell me what it says, I'll try to give you an answer.
4 0
3 years ago
PLEASE I NEED HELP WITH THIS
Ber [7]

Given:

The figure of a circle.

To find:

The measure of arc AD and measure of each arc.

Solution:

The measure of arc is equal to the central angle of that arc.

The central angle of arc AD is 105 degrees. So,

m(arc(AD))=105^\circ

The central angle of arc BC is 35 degrees. So,

m(arc(BC))=35^\circ

The central angle of arc CD is 50 degrees. So,

m(arc(CD))=50^\circ

The central angle of a complete circle is 360 degrees. So,

m(arc(AD))+m(arc(BC))+m(arc(CD))+m(arc(AB))=360^\circ

105^\circ+35^\circ+50^\circ+m(arc(AB))=360^\circ

190^\circ+m(arc(AB))=360^\circ

m(arc(AB))=360^\circ-190^\circ

m(arc(AB))=170^\circ

Therefore, the measure of arc AD is 105°, the measure of arc BC is 35°, the measure of arc CD is 50° and the measure of arc AB is 170°

3 0
2 years ago
A line passes through the points......​
Kobotan [32]
Should be the first one
8 0
3 years ago
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