Answer:
<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>
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Step-by-step explanation:
yacht speed = 20 knots
yacht bearing = 185° = 85° below the negative horizontal x-axis
wind speed = 15 knots
wind bearing = 290° = 20° above the negative horizontal x-axis
we find the x and y components of the boat velocities
for yacht,
x component = -20 cos 85° = -1.74 knots
y component = -20 sin 85° = -19.92 knots
for the wind,
x component = -15 cos 20° = -14.09 knots
y component = 15 sin 20° = 5.13 knots
total x component Vx = -1.74 + (-14.09) = -15.83 knots
total y component Vy = -19.92 + 5.13 = -14.79 knots
Resultant speed of the boat =
==>
= <em>21.66 knot</em>
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direction of boat = ![tan^{-1} \frac{Vy}{Vx}](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20%5Cfrac%7BVy%7D%7BVx%7D)
==>
= <em>43.05°</em>
Answer:
n = 0
Step-by-step explanation:
6 = 1 - 2n + 5
6 = 6 -2n
0 = -2n
n = 0
36000 lbs = 16329.325 kg
18 ton = 18000kg
18 ton is greater
Answer:
(x-3)(x+2)
Step-by-step explanation:
x^2-x-6
i.e,x^2-3x+2x-6
i.e,x(x-3)+2(x-3)
i.e,(x-3)(x+2)
hop it helps ✌️:)