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babymother [125]
3 years ago
8

Graphing on a scatter diagram 9/4x+1/2 (-2, -4) (2, 5)

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0
The does this differ from the original points is -32.5
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HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N
AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
3 years ago
Help please and thanks! I always give brainliest! (Explain too please)
qwelly [4]

Answer:

A. 2/3

Opposite Sides of a Parallelogram

The two pairs of sides in a parallelogram are parallel to each other.

Parallel lines have the same slope.

The slope of the opposite sides of a parallelogram are congruent (equal in measure).

Given:

Slope of PQ = 2/3

Slope of QR = -1/2

For PQRS to be a parallelogram, the slope of SR must be same as the slope of PQ.

This implies that: Slope of SR = Slope of PQ = 2/3.

Therefore, based on the properties of a parallelogram, the slope of SR for PQRS to be a parallelogram would be: 2/3.

4 0
2 years ago
Which of the following equations is of a parabola with a vertex at (3, 0)?
bixtya [17]

Answer:

D. y = (x - 3)²

Step-by-step explanation:

The parabola formula in vertex form is:

y = a(x - h)² + k

where the vertex is located at (h, k). Replacing with vertex (3, 0) we get:

y = a(x - 3)² + 0

y = a(x - 3)²

In all possible options the leading coefficient <em>a</em> is equal to one. Therefore:

y = (x - 3)²

7 0
3 years ago
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