1. Higher speed
2. New features
3. Less bugs
4. Upgrades
Answer:
- Divide the resources into three parts using the corresponding process 1, process 1, and process 2 formats to maximize the use of the resources.
- Get the expected revenue by calculating the product of the total perfume in ounce and the price of an ounce of perfume.
- Increase the advertisement hours of the product.
- subtract the advert fee from the generated revenue to get the actual revenue.
- subtract the cost of production from the actual revenue to get the actual profit.
Explanation:
The get maximum profit, all the resources must be exhausted in production. The labor is divided into a ratio of 1:1:2 ( which is 5000, 5000, 1000), while the chemical units are in the ratio of 2:2:3 (10000,10000,15000). This would produce in each individual processes; 15000, 15000 and 25000 oz, which is a total of 55000 oz of perfume.
The expected revenue is $275000. If 1000oz from the 55000oz of perfume is sold without advertisement, model Jenny's awareness of the perfume increases the demand by 200oz per hour, therefore, 24hours would field 4800oz demanded, which would only take 270 hours to distribute all remaining perfumes.
The cost of production would be $130000 for labor and chemical resources plus the advert cost of $27000 ( 270 hours by 100) which is a total cost of $157000. The actual profit is $118000 ( $275000 - $157000).
Answer:
Material systems developer typically combines the skills of a programmer with the multitasking expectations of developing 3 dimensional models of objects, enhancing the graphical effects.
Answer:
FF-FF-FF-FF-FF-FF and 255.255.255.255
Explanation:
FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.
255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.
Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255
Answer:
Answered below
Explanation:
//Program is written in Python programming language
def charCnt( fileName, char){
if not fileName.exists( ):
return sys.exit(1)
else:
openFile = open("$fileName.txt", "r")
readFile = openFile.read( )
fileLength = len (readFile)
count = 0
for character in range(fileLength):
if readFile[character] == char:
count++
openFile.close( )
return count
}
