Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
Answer:
The computer will store 8.05 *10^10 bytes of information.
Explanation:
This is the same as saying that the computer will now have 80.51 Gigabytes ( 1gb = 1.000.000.000 bytes) of storage. In this case, the number is represented in its decimal form, and the previous one is displayed in Scientific Notation.
HTML: Hypertext Markup Language. It's used in conjunction with CSS (Cascading Style Sheets), which implements presentation (adding color, positioning elements, etc.) and JavaScript (you'll often see this referred to as JS), which implements functionality (like clicking on buttons) for webpages.
Answer: This is a python code
def lightyear():
rate=3*100000000 //speed of light
seconds=365*24*60*60 //number of seconds in 1 year
return str((rate*seconds)/1000)+" km" //distance=speed x time
print(lightyear()) //will print value of light hear in kilometers
OUTPUT :
9460800000000.0 km
Explanation:
In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.
