Answer: Children tickets cost 7.50
Adult tickets cost 12.50
Step-by-step explanation:
Let a represent adult tickets
Let c represent child tickets
On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:
6a + 5c = 112.50 ...... equation i
On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:
8a + 4c = 130 ....... equation ii
6a + 5c = 112.50 ...... equation i
8a + 4c = 130 ....... equation ii
Multiply equation i by 4
Multiply equation ii by 5
24a + 20c = 450 ........ equation iii
40a + 20c = 650 ......... equation iv
Subtract iii from iv
16a = 200
a = 200/16
a = 12.50
Adult tickets cost 12.50
From equation ii,
8a + 4c = 130
8(12.50) + 4c = 130
100 + 4c = 130
4c = 130 - 100
4c = 30
c = 30/4
c = 7.50
Children tickets cost 7.50
Answer:
53 lies between 7.2² and 7.3²
Step-by-step explanation:
Estimating a root to the nearest tenth can be done a number of ways. The method shown here is to identify the tenths whose squares bracket the value of interest.
You have answered the questions of parts 1 to 3.
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<h3>4.</h3>
You are given that ...
7.2² = 51.84
7.3² = 53.29
This means 53 lies between 7.2² and 7.3², so √53 lies between 7.2 and 7.3.
53 is closer to 7.3², so √53 will be closer to 7.3 than to 7.2.
7.3 is a good estimate of √53 to the tenths place.
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<em>Additional comment</em>
For an integer n that is the sum of a perfect square (s²) and a remainder (r), the square root is between ...
s +r/(2s+1) < √n < s +r/(2s)
For n = 53 = 7² +4, this means ...
7 +4/15 < √53 < 7 +4/14
7.267 < √53 < 7.286
Either way, √53 ≈ 7.3.
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The root is actually equal to the continued fraction ...
Since she needs 3 1/2 for 5, and you need to find one batch, get 3 1/2 and divide it by 5. Change 3 1/2 to an improper fraction (7/2). Now use KCS (keep change switch) Keep the 7/2, change division to multiplication, and switch 5/1 to 1/5. (7/2)•(1/5)
Answer:
Step-by-step explanation:
